Friday, August 3, 2007

Puzzle 4

Q1 : You go to a tap that delivers an unlimited amount of water. You have two empty containers, one of 7 liters, the other of 11 liters. At each operation one container must be completely filled or completely emptied. How many operations are required to fill one of the containers with exactly 6 liters of water? Kindly indicate the steps
Note: The containers are shaped so irregularly that you can't measure the required amount other than by making use of the other container.
Q2 : An eight gallon container is full and both a three gallon container and a five gallon container are empty. Without using any other containers, divide the water into two equal amounts.
Note: The containers are shaped so irregularly that you can't measure the required amount other than by making use of the other containers. There are two ways to solve this puzzle.

4 comments:

manu said...

answer Q2:
c8 8 lt container
c5 5 lt container
c3 3 lt container

Step 1From C8 to C5 and from c5 to c3

now c8-- 3 lt
c5-- 2 lt
c3-- 3 lt

Step 2 From c3 to c8 then c5 to c3

now c8-- 6 lt
c5-- 0 lt
c3-- 2 lt

Step 3 from c8 to c5 and c5 to c3

now c8 - 1 lt
c5 - 4 lt
c3 - 3 lt
now c3 to c8 and problem is solved

Mohit said...

answer Q2:
c8 8 lt container
c5 5 lt container
c3 3 lt container

Step 1From C8 to C5 and from c5 to c3

now c8-- 3 lt
c5-- 2 lt
c3-- 3 lt

Step 2 From c3 to c8 then c5 to c3

now c8-- 6 lt
c5-- 0 lt
c3-- 2 lt

Step 3 from c8 to c5 and c5 to c3

now c8 - 1 lt
c5 - 4 lt
c3 - 3 lt
now c3 to c8 and problem is solved

nikhil said...

(11 lit) (7 lit)
0 +7
+7 0
7 +7
7+4 3
-11 3
+3 0
3 +7
3+7 0
10 +7
10+1 6

thus 6 remain in the 7 lit container

Unknown said...

Krupa:
Q1
C11-Full
C11->C7, Empty C7 C11-4, C7-0
C11->C7 C11-0, C7-4
C11->C7 Empty C7 C11-8, C7-0
C11->C7 Empty C7 C11-1, C7-0
C11->C7 C11-0, C7-1
C11->C7 Empty C7 C11-5, C7-0
C11->C7 C11-0, C7-5
C11->C7 Empty C7 C11-2, C7-0
C11->C7 C11-0, C7-2
C11->C7 Empty C7 C11-6, C7-0